← All topics⚽ Sphere, Pyramid & SolidsMaths
Mensuration · Topic 7 of 7

⚽ Sphere, Pyramid & Solids

3 exam question types, fully solved

A sphere is a perfectly round solid — every point on its surface is the same distance (the radius ) from the centre. SSC pairs it with the hemisphere (half a sphere), the pyramid, the prism and the all-important melting & recasting idea. The good news: a handful of formulas plus the habit of writing and cancelling the 7 first carry the whole topic.

The formulas that crack every solids question

• Sphere: volume and surface area .

• Hemisphere (half a sphere): volume , curved surface , and total surface (the curved part plus the flat circular lid). Read solid vs hollow carefully — a bowl has no lid, so it uses only the curved .

• Pyramid (pointed top on a flat base): volume , and surface , where is the slant height. Always use the slant height for the faces, not the vertical height.

• Prism (same cross-section all the way up): volume . There is no one-third here — that is the single biggest trap, because a pyramid is exactly one-third of the prism on the same base.

• Combination solids: a shape built from parts (an ice-cream cone is a cone topped by a hemisphere; a capsule is a cylinder with a hemisphere at each end). Just add the volumes of the parts, and add only the exposed surfaces.

• Melting & recasting: when a solid is melted and reshaped, the volume stays the same. So set and solve. For identical small pieces, ; the (and any other constant) cancels straight away.

• Ratios of similar solids: volume grows as the cube of length, surface as the square. So radii in ratio give volumes in ratio and surface areas in ratio .

📦3D Shape CalculatorSelect a solid · Enter dimensions · Get Volume & Surface Area
Volumel × b × h72units³
Lateral SA2h(l + b)60units²
Total SA2(lb + bh + lh)108units²
Space Diagonal:7.81 units
Step-by-Step Working
1.Volume = l × b × h = 6 × 4 × 3 = 72 units³
2.LSA = 2h(l + b) = 2 × 3 × (6 + 4) = 60 units²
3.TSA = 2(lb + bh + lh) = 2(24 + 12 + 18) = 108 units²
4.Diagonal = √(l² + b² + h²) = √(36 + 16 + 9) = 7.81 units

Quick check — the surface area of a sphere of radius 7 cm is cm².

Notice how melting links everything: a big sphere becomes many small cylinders or spheres, yet the total volume never changes. Write the two volumes as a fraction, cancel the , and the count drops out — for identical spheres it is simply the cube of the radius ratio, e.g..

📝Practice Questions

Q1The volume of a sphere of radius 7 cm is (π = 22/7):

Q2A sphere of radius 6 cm is melted into small spheres of radius 1 cm. How many are formed?

Q3The volume of a pyramid with base area 24 cm² and height 15 cm is:

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Real exam questions — Sphere, Pyramid & Solids

4 question types · 12 solved examples from real SSC papers

Spheres, hemispheres, pyramids and prisms — plus the melting-and-recasting trick where the volume stays constant. Every solution takes π=227\pi=\dfrac{22}{7}, cancels the 7 first, and ends with the exam shortcut.

How to solve this type
Pick the right formula first: volume of a sphere is 43πr3\dfrac{4}{3}\pi r^3, its surface area is 4πr24\pi r^2. A solid hemisphere has total surface 3πr23\pi r^2 (curved 2πr22\pi r^2 plus the circular base πr2\pi r^2); a hollow bowl uses only 2πr22\pi r^2. Take π=227\pi=\dfrac{22}{7} and cancel the 7 before multiplying.

A sphere has radius 7 cm. Find its volume. (Take π=227\pi=\dfrac{22}{7})

A13801380 cm³B1437.31437.3 cm³C15001500 cm³D13201320 cm³

Find the total surface area of a solid hemisphere of radius 7 cm. (Take π=227\pi=\dfrac{22}{7})

A420420 cm²B484484 cm²C440440 cm²D462462 cm²

The surface area of a sphere is 5544 cm². Find its radius. (Take π=227\pi=\dfrac{22}{7})

A2121 cmB1818 cmC2424 cmD1414 cm