A cylinder, a cone and a frustum (a bucket — a cone with its tip sliced off) are the round 3-D solids SSC asks about again and again. Each one has just three things to know — volume, curved surface area and total surface area — and writing π=722 lets the 7 cancel early so the arithmetic stays small.
The cylinder (radius r, height h)
• Volume=πr2h — the base area πr2 times the height. Find the base area first, then multiply by h.
• Curved surface area (CSA)=2πrh — only the side, with no top or bottom lid.
• Total surface area (TSA)=2πrh+2πr2=2πr(r+h) — the side plus both circular ends. Always use the factored form 2πr(r+h); it is one multiplication and stops you dropping the two lids.
The cone (radius r, height h, slant height l)
• Slant heightl=r2+h2 — the slant is the hypotenuse of the right triangle made by the radius and the vertical height. Lean on the Pythagoras triplets (3,4,5),(5,12,13),(8,15,17),(7,24,25).
• Volume=31πr2h — exactly one-third of the cylinder that shares the same base and height (it takes 3 cones of water to fill that cylinder). Never forget the 31.
• CSA=πrl, and TSA=πrl+πr2=πr(l+r) — curved face plus the circular base. Use the slant height l here, never the vertical height.
The frustum / bucket (radii R and r, height h, slant height l)
• Slant heightl=h2+(R−r)2 — note it uses the difference of the radii, not the sum.
• Volume=31πh(R2+Rr+r2) — keep the middle Rr term; it is the most common thing to drop.
• CSA=πl(R+r) (the radii enter as the SUM here), and TSA=πl(R+r)+πR2+πr2 — the curved side plus the big and small circular ends.
The exam habit to build: take π=722 whenever a radius is a multiple of 7 and cancel that 7 before multiplying — for example 722×72=22×7=154. Cancel first, multiply last.
📦3D Shape CalculatorSelect a solid · Enter dimensions · Get Volume & Surface Area
Quick check — a cylinder whose base area is πr2=154 cm² and whose height is 10 cm has volume 154×10= cm³.
Use the calculator above to check any solid, then try the practice set. Keep one fact in your pocket: a cone is exactly one-third of the cylinder with the same base and height, and a frustum is just the wide part of a cone left after the narrow tip is cut away.
📝Practice Questions
Q1A cylinder has radius 7 cm and height 10 cm. Its volume is (π = 22/7):
Q2A cone has radius 6 cm and height 8 cm. Its slant height is:
Q3A frustum has radii 10 cm and 6 cm and height 3 cm. Its slant height is:
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Real exam questions — Cylinder, Cone & Frustum
3 question types · 9 solved examples from real SSC papers
Cylinders, cones and the frustum (a bucket — a cone with its tip sliced off) are the round 3-D solids SSC loves. Master volume, CSA and TSA for each, write π=722 to cancel the 7 early, and remember a cone is exactly one-third of its matching cylinder.
How to solve this type
A cylinder has three things to know: volume =πr2h (base area × height), curved surface area =2πrh (the side only), and total surface area =2πrh+2πr2=2πr(r+h) (side plus both circular lids). Take π=722 when the radius is a multiple of 7 and cancel that 7 first. Read carefully whether CSA or TSA is wanted — that is the most common trap.
A cylinder has radius r=7 cm and height h=10 cm. Find its volume. (Take π=722)
A1078 cm³B1540 cm³C1408 cm³D770 cm³
Find the curved surface area (CSA) of a cylinder with r=7 cm and h=15 cm. (Take π=722)
A640 cm²B660 cm²C680 cm²D620 cm²
A cylinder has r=14 cm and h=5 cm. Find its total surface area (TSA). (Take π=722)