← All topics🥫 Cylinder, Cone & FrustumMaths
Mensuration · Topic 6 of 7

🥫 Cylinder, Cone & Frustum

3 exam question types, fully solved

A cylinder, a cone and a frustum (a bucket — a cone with its tip sliced off) are the round 3-D solids SSC asks about again and again. Each one has just three things to know — volume, curved surface area and total surface area — and writing lets the 7 cancel early so the arithmetic stays small.

The cylinder (radius r, height h)

• Volume — the base area times the height. Find the base area first, then multiply by .

• Curved surface area (CSA) — only the side, with no top or bottom lid.

• Total surface area (TSA) — the side plus both circular ends. Always use the factored form ; it is one multiplication and stops you dropping the two lids.

The cone (radius r, height h, slant height l)

• Slant height — the slant is the hypotenuse of the right triangle made by the radius and the vertical height. Lean on the Pythagoras triplets .

• Volume — exactly one-third of the cylinder that shares the same base and height (it takes 3 cones of water to fill that cylinder). Never forget the .

• CSA , and TSA — curved face plus the circular base. Use the slant height here, never the vertical height.

The frustum / bucket (radii R and r, height h, slant height l)

• Slant height — note it uses the difference of the radii, not the sum.

• Volume — keep the middle term; it is the most common thing to drop.

• CSA (the radii enter as the SUM here), and TSA — the curved side plus the big and small circular ends.

The exam habit to build: take whenever a radius is a multiple of 7 and cancel that 7 before multiplying — for example . Cancel first, multiply last.

📦3D Shape CalculatorSelect a solid · Enter dimensions · Get Volume & Surface Area
Volumel × b × h72units³
Lateral SA2h(l + b)60units²
Total SA2(lb + bh + lh)108units²
Space Diagonal:7.81 units
Step-by-Step Working
1.Volume = l × b × h = 6 × 4 × 3 = 72 units³
2.LSA = 2h(l + b) = 2 × 3 × (6 + 4) = 60 units²
3.TSA = 2(lb + bh + lh) = 2(24 + 12 + 18) = 108 units²
4.Diagonal = √(l² + b² + h²) = √(36 + 16 + 9) = 7.81 units

Quick check — a cylinder whose base area is cm² and whose height is 10 cm has volume cm³.

Use the calculator above to check any solid, then try the practice set. Keep one fact in your pocket: a cone is exactly one-third of the cylinder with the same base and height, and a frustum is just the wide part of a cone left after the narrow tip is cut away.

📝Practice Questions

Q1A cylinder has radius 7 cm and height 10 cm. Its volume is (π = 22/7):

Q2A cone has radius 6 cm and height 8 cm. Its slant height is:

Q3A frustum has radii 10 cm and 6 cm and height 3 cm. Its slant height is:

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Real exam questions — Cylinder, Cone & Frustum

3 question types · 9 solved examples from real SSC papers

Cylinders, cones and the frustum (a bucket — a cone with its tip sliced off) are the round 3-D solids SSC loves. Master volume, CSA and TSA for each, write π=227\pi=\dfrac{22}{7} to cancel the 7 early, and remember a cone is exactly one-third of its matching cylinder.

How to solve this type
A cylinder has three things to know: volume =πr2h= \pi r^2 h (base area ×\times height), curved surface area =2πrh= 2\pi r h (the side only), and total surface area =2πrh+2πr2=2πr(r+h)= 2\pi r h + 2\pi r^2 = 2\pi r(r+h) (side plus both circular lids). Take π=227\pi=\dfrac{22}{7} when the radius is a multiple of 7 and cancel that 7 first. Read carefully whether CSA or TSA is wanted — that is the most common trap.

A cylinder has radius r=7r = 7 cm and height h=10h = 10 cm. Find its volume. (Take π=227\pi = \dfrac{22}{7})

A10781078 cm³B15401540 cm³C14081408 cm³D770770 cm³

Find the curved surface area (CSA) of a cylinder with r=7r = 7 cm and h=15h = 15 cm. (Take π=227\pi = \dfrac{22}{7})

A640640 cm²B660660 cm²C680680 cm²D620620 cm²

A cylinder has r=14r = 14 cm and h=5h = 5 cm. Find its total surface area (TSA). (Take π=227\pi = \dfrac{22}{7})

A15401540 cm²B16001600 cm²C16721672 cm²D17441744 cm²