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Mean, Median & Mode · Topic 5 of 6

⚖️ Empirical Relation & Effects

4 exam question types, fully solved

This topic gathers the questions that relate the three averages and the questions that ask what happens when the data changes. Both reward a quick rule over slow computation.

The empirical relation

For a moderately skewed distribution, Karl Pearson's relation ties the three together:

Rearrange to find whichever is missing: and . A neat shortcut: , so the Mean–Mode gap is always three times the Mean–Median gap. Memory hook: the bigger coefficient rides with Median (the longer word).

When observations change

• Mean — add / remove / replace / misread: everything runs on . Fix the total, then divide by the right count. For a replacement the count stays the same and the mean shifts by ; for a misread, corrected total wrong total wrong value correct value.

• Median — positional: it depends only on the middle position, not on extreme sizes. A change moves the median only if it touches the middle value, or if adding/removing an item shifts the middle position. Otherwise the median is unmoved — even when the mean changes.

• Linear transformation of the mean: if every value becomes , the mean follows the identical rule, , and the count is irrelevant. Apply the same operations in the same order to the old mean.

📊Statistics ExplorerEnter up to 10 numbers

Using 8 values (max 10)

Mean=5.5Median=6
— Mean— Median● Mode (larger dot)● Other values
Sorted Array
23457779
Mean
(4 + 7 + 2 + 9 + 7 + 3 + 7 + 5) / 8
5.5
Median
Avg of positions 4 and 5 = (5 + 7) / 2
6
Mode
7 (unimodal)
Distribution insight: The mean is smaller than the median — the data is left-skewed (pulled by small outliers).
Empirical Check: Mode = 3×Median − 2×Mean
3×6 − 2×5.5 = 7 (actual mode: 7)

If mean = 20 and median = 24, then mode .

📝Practice Questions

Q1If mean = 20 and median = 24, the mode (Mode = 3 Median − 2 Mean) is:

Q2The mean of 8 numbers is 30. One number 26 is replaced by 50. The new mean is:

Q3The median of 7 sorted values is 40. The two largest values are each doubled. The median:

📚

Real exam questions — Empirical Relation & Effects

4 question types · 16 solved examples from real SSC papers

Three averages are linked by Mode=3 Median−2 Mean\text{Mode}=3\,\text{Median}-2\,\text{Mean}. For “effect of change” questions, the mean follows the total while the median follows only the middle position.

How to solve this type
For a moderately skewed distribution, Karl Pearson's empirical relation links the three: Mode=3 Median−2 Mean\text{Mode}=3\,\text{Median}-2\,\text{Mean}.
Rearrange as needed: Median=Mode+2 Mean3\text{Median}=\dfrac{\text{Mode}+2\,\text{Mean}}{3} and Mean=3 Median−Mode2\text{Mean}=\dfrac{3\,\text{Median}-\text{Mode}}{2}.
A neat consequence: (Mean−Mode)=3(Mean−Median)(\text{Mean}-\text{Mode})=3(\text{Mean}-\text{Median}), so the Mean–Mode gap is always THREE times the Mean–Median gap. The median always lies between the mean and the mode.
Memory hook: the bigger coefficient 3 goes with Median (the longer word).

For a distribution, mean = 25 and mode = 31. Find the median.

A26B27C29D28

In a moderately skewed distribution mean = 15 and median = 17. Find the mode.

A22B19C20D21

If mode = 80 and mean = 68, find the median.

A73B71C72D70

For a frequency distribution, mean − mode = 12. Find mean − median.

A2B8C4D6