⚖️ Empirical Relation & Effects
4 exam question types, fully solvedThis topic gathers the questions that relate the three averages and the questions that ask what happens when the data changes. Both reward a quick rule over slow computation.
For a moderately skewed distribution, Karl Pearson's relation ties the three together:
Rearrange to find whichever is missing: and . A neat shortcut: , so the Mean–Mode gap is always three times the Mean–Median gap. Memory hook: the bigger coefficient rides with Median (the longer word).
• Mean — add / remove / replace / misread: everything runs on . Fix the total, then divide by the right count. For a replacement the count stays the same and the mean shifts by ; for a misread, corrected total wrong total wrong value correct value.
• Median — positional: it depends only on the middle position, not on extreme sizes. A change moves the median only if it touches the middle value, or if adding/removing an item shifts the middle position. Otherwise the median is unmoved — even when the mean changes.
• Linear transformation of the mean: if every value becomes , the mean follows the identical rule, , and the count is irrelevant. Apply the same operations in the same order to the old mean.
Using 8 values (max 10)
If mean = 20 and median = 24, then mode .
Q1If mean = 20 and median = 24, the mode (Mode = 3 Median − 2 Mean) is:
Q2The mean of 8 numbers is 30. One number 26 is replaced by 50. The new mean is:
Q3The median of 7 sorted values is 40. The two largest values are each doubled. The median:
Real exam questions — Empirical Relation & Effects
4 question types · 16 solved examples from real SSC papersThree averages are linked by . For “effect of change” questions, the mean follows the total while the median follows only the middle position.
Rearrange as needed: and .
A neat consequence: , so the Mean–Mode gap is always THREE times the Mean–Median gap. The median always lies between the mean and the mode.
Memory hook: the bigger coefficient 3 goes with Median (the longer word).
For a distribution, mean = 25 and mode = 31. Find the median.
In a moderately skewed distribution mean = 15 and median = 17. Find the mode.
If mode = 80 and mean = 68, find the median.
For a frequency distribution, mean − mode = 12. Find mean − median.
