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Mean, Median & Mode Β· Topic 6 of 6

πŸ“Š Variance & Standard Deviation

1 exam question type, fully solved

Averages tell you the centre; dispersion tells you how spread out the data is around that centre. The two exam measures are variance and its square root, the standard deviation.

Spread, square roots and scaling

β€’ Variance is the average squared distance from the mean: . Standard deviation is its square root: . Always finish with the square root if SD is asked.

β€’ Shortcut from totals: β€” the mean of the squares minus the square of the mean. Rearranged: .

β€’ Scaling rules for : the mean becomes , the SD becomes , and the variance becomes . Adding a constant never changes the spread β€” only multiplying does. So ignore any β€œβ€¦ and then add 3” when SD or variance is asked.

β€’ AP shortcut: for an arithmetic progression with common difference and terms, .

πŸ“ŠStatistics ExplorerEnter up to 10 numbers

Using 8 values (max 10)

Mean=5.5Median=6
β€” Meanβ€” Median● Mode (larger dot)● Other values
Sorted Array
23457779
Mean
(4 + 7 + 2 + 9 + 7 + 3 + 7 + 5) / 8
5.5
Median
Avg of positions 4 and 5 = (5 + 7) / 2
6
Mode
7 (unimodal)
Distribution insight: The mean is smaller than the median β€” the data is left-skewed (pulled by small outliers).
Empirical Check: Mode = 3Γ—Median βˆ’ 2Γ—Mean
3Γ—6 βˆ’ 2Γ—5.5 = 7 (actual mode: 7)

If the variance is 36, the standard deviation is .

πŸ“Practice Questions

Q1If the variance of a data set is 25, its standard deviation is:

Q2Each value of a data set is increased by 7. The standard deviation:

Q3A data set has SD = 3. Each value is multiplied by 4. The new SD is:

πŸ“š

Real exam questions β€” Variance & Standard Deviation

1 question types Β· 5 solved examples from real SSC papers

Variance is the average squared distance from the mean and SD =variance=\sqrt{\text{variance}}. Adding a constant leaves the spread unchanged; multiplying by aa scales SD by ∣a∣|a| and variance by a2a^2.

How to solve this type
Variance Οƒ2\sigma^2 is the average of the squared distances from the mean: Οƒ2=βˆ‘(xβˆ’xΛ‰)2n\sigma^2=\dfrac{\sum (x-\bar{x})^2}{n}. Standard deviation is its square root: Οƒ=Οƒ2\sigma=\sqrt{\sigma^2}.
Computing shortcut from totals: Οƒ2=βˆ‘x2nβˆ’(βˆ‘xn)2\sigma^2=\dfrac{\sum x^2}{n}-\left(\dfrac{\sum x}{n}\right)^2 (the mean of the squares minus the square of the mean). Rearranged: βˆ‘x2=n(Οƒ2+xΛ‰2)\sum x^2=n(\sigma^2+\bar{x}^2).
Scaling rules β€” for y=ax+by=ax+b: the mean becomes axΛ‰+ba\bar{x}+b, the SD becomes ∣aβˆ£Οƒ|a|\sigma, and the variance becomes a2Οƒ2a^2\sigma^2. Adding a constant bb shifts the data but does NOT change the spread, so it leaves variance and SD untouched.
For an AP with common difference dd and nn terms, Οƒ2=d2(n2βˆ’1)12\sigma^2=\dfrac{d^2(n^2-1)}{12}.

Find the variance of 2, 4, 6, 8, 10.

A9B7C6D8

If Ξ£x = 120, Ξ£xΒ² = 1600 and n = 10, find the standard deviation.

A6B8C2D4

The mean of 5 numbers is 15 and the variance is 9. Find the sum of their squares.

A1200B1150C1125D1170

The mean of 5 values is 10 and the variance is 4. Each value is doubled. Find the new mean and new SD.

A20, 2B20, 4C20, 8D10, 4

If the variance of 5 values is 0.81, the standard deviation is:

A0.9B2.7C0.027D0.09