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Boats & Streams Β· Topic 3 of 5

πŸ” Round Trip & Return Journey

2 exam question types, fully solved

A round trip is one stretch of length covered once downstream and once upstream. The fast downstream leg and the slow upstream leg take different times, so you must handle them separately β€” never divide the total distance by the still-water speed.

Total time, distance from time, and the true average speed

Net speeds first: and . The total there-and-back time is .

β€’ When the round-trip time is given and you need the one-way distance, skip adding fractions and use (cancel against before multiplying).

β€’ The round-trip average speed is , not the plain average of and β€” the slow upstream leg drags the average below the midpoint.

β€’ Speed-doubling puzzles fall out of the round-trip time formula : take the ratio of the two cases and the distance cancels.

β›΅Boats & Streams SimulatorSet speeds Β· enter a distance Β· see the full round trip
current β†’
Boat speed (B) in still water
km/h
Stream speed (S / current)
km/h
Downstream (β†’)B + S = 14 km/h
Upstream (←)B βˆ’ S = 6 km/h
Round trip β€” one-way distance dkm
LEG 1 Β· DOWNSTREAM (fast)60 Γ· 14 = 4.29 h
LEG 2 Β· UPSTREAM (slow)60 Γ· 6 = 10 h
Total time = d/D + d/U
4.29 + 10 = 14.29 h
Round-trip average = DΓ—U Γ· B
14Γ—6 Γ· 10 = 8.4 km/h
below B = 10 β€” the slow leg drags it down
Shortcut check (time given β†’ distance): d = TΓ—DΓ—U Γ· (D+U) = 14.29Γ—14Γ—6 Γ· 20 = 60 km βœ“

With , and a round trip of 8 h, the one-way distance = km.

πŸ“Practice Questions

Q1A boat goes 4 km/h upstream and 12 km/h downstream. A round trip takes 8 h. The one-way distance is:

Q2A boat rows at 10 km/h in still water on a 2 km/h stream. It goes 48 km and returns. Total time is:

Q3A boat has downstream speed 12 km/h, upstream speed 6 km/h and still-water speed 9 km/h. Its round-trip average speed is:

πŸ“š

Real exam questions β€” Round Trip & Return Journey

2 question types Β· 7 solved examples from real SSC papers

Solve any boats-and-streams round trip, from same-distance up-and-back legs to return-journey time-and-speed puzzles, using clean net-speed shortcuts.

How to solve this type
First write the net speeds: D=b+sD=b+s and U=bβˆ’sU=b-s. The total round-trip time is dD+dU\dfrac{d}{D}+\dfrac{d}{U}. When the total time TT is given and you need the distance, skip adding fractions and use d=TΓ—DΓ—UD+Ud=\dfrac{T\times D\times U}{D+U}. The round-trip AVERAGE speed is DΓ—Ub\dfrac{D\times U}{b}, NOT the plain average of DD and UU β€” the slow upstream leg drags it down.

A boat goes 5 km/h upstream and 15 km/h downstream. It makes a round trip (one way and back) in 8 hours. Find the one-way distance.

A30 kmB40 kmC45 kmD50 km

A boat's speed in still water is 6 km/h and the stream flows at 2 km/h. The boat rows to a point 24 km away and comes back. Find the total time.

A8 hB10 hC12 hD9 h

A boat goes 25 km/h upstream and 35 km/h downstream. The total round-trip time is 12 hours. Find the one-way distance.

A160 kmB150 kmC175 kmD180 km

A man rows to a place 48 km away and returns, taking 14 hours in all. His downstream and upstream speeds are in the ratio 4:3. Find the speed of the stream.

A3.5 km/hB1.5 km/hC1.8 km/hD1 km/h