π» Successive Discounts
2 exam question types, fully solvedTwo discounts one after another are never their sum β the second comes off the already-reduced price, so the real discount is always less than a + b.
Two discounts a% and b% equal a single discount of a + b β %. So 20% and 10% give 30 β 2 = 28%, never 30%.
β’ Or multiply the surviving fractions: is the part still paid; 1 minus it is the discount.
β’ For three discounts, combine two into one equivalent, then combine with the third β or chain the fractions once: 25%, 20% and 10% leave paid, a single 46% discount (tag βΉ600 β pay βΉ324).
β’ βBuy n, get m freeβ is a discount of : buy 3 get 1 free β = 25% off, never 33%.
Slabs & conditions: for βX% off above βΉNβ, use only the single highest slab reached β they don't stack. And β>βΉNβ excludes the exact value βΉN.
Discounts of 20% and 10% equal a single discount of 30 β 2 = %.
Q1Two successive discounts of 10% and 20% equal a single discount of:
Q2On MP βΉ500, discounts of 20% then 10% give SP:
Q3Two equal discounts giving a single 19% discount means each is:
Real exam questions β Successive Discounts
2 question types Β· 6 solved examples from real SSC papersTwo discounts in a row are never their sum β the second comes off the reduced price. Use the single equivalent.
Two successive discounts of 20% and 10% are equal to a single discount of:
A shirt has 25% off, plus 20% for cash, plus 10% for a loyal customer. She paid βΉ324. The price tag was (in βΉ):
On a bill, the difference between a single 27% discount and two successive discounts of 20% and 10% was βΉ56. The bill amount was:
