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Mean, Median & Mode Β· Topic 2 of 6

πŸ“ Median

2 exam question types, fully solved

The median is the value bang in the middle once the data is lined up in order. Half the values sit below it and half above. Unlike the mean, it does not care how big the extreme values are β€” so it is resistant to outliers.

Sort first, then find the middle

Step 1 is always sorting β€” many exam traps hand you unsorted data hoping you grab the middle of the raw list.

β€’ Odd count: the median is the single value at position . For , that is the 5th value.

β€’ Even count: there is no single middle, so average the two central values, at positions and . For , that is .

β€’ Find a hidden value: if the median is given, drop the unknown into the middle position and read it off (odd ), or solve the small average equation (even ).

β€’ Grouped data (class intervals): you cannot see single values, so interpolate inside the class holding the middle:

where = lower limit of the median class, = cumulative frequency before it, = its frequency, = class width. The median class is the first whose cumulative frequency reaches .

πŸ“ŠStatistics ExplorerEnter up to 10 numbers

Using 8 values (max 10)

Mean=5.5Median=6
β€” Meanβ€” Median● Mode (larger dot)● Other values
Sorted Array
23457779
Mean
(4 + 7 + 2 + 9 + 7 + 3 + 7 + 5) / 8
5.5
Median
Avg of positions 4 and 5 = (5 + 7) / 2
6
Mode
7 (unimodal)
Distribution insight: The mean is smaller than the median β€” the data is left-skewed (pulled by small outliers).
Empirical Check: Mode = 3Γ—Median βˆ’ 2Γ—Mean
3Γ—6 βˆ’ 2Γ—5.5 = 7 (actual mode: 7)

Sorted data 2, 5, 8, 11, 14 has 5 values, so the median is the 3rd one: .

πŸ“Practice Questions

Q1Find the median of 9, 3, 7, 1, 5 (sort first).

Q2Find the median of 4, 8, 6, 2 (sort first).

Q3For grouped data the median formula uses cf, which means:

πŸ“š

Real exam questions β€” Median (ungrouped & grouped)

2 question types Β· 10 solved examples from real SSC papers

Sort the data, then the median is the middle value (odd nn) or the average of the two middles (even nn). For class intervals, interpolate with Median=l+n/2βˆ’cffΓ—h\text{Median}=l+\dfrac{n/2-cf}{f}\times h.

How to solve this type
The median is the MIDDLE value of the data after you SORT it (sorting is non-negotiable β€” it is step 1).
Odd count nn: the median sits at position n+12\dfrac{n+1}{2}, a single real value.
Even count nn: there is no single middle, so the median is the average of the two central values, at positions n2\dfrac{n}{2} and n2+1\dfrac{n}{2}+1.
The median is resistant to outliers β€” a huge or tiny value at the ends does not move it.
If the median is given and a value is unknown, place the unknown at the middle position and read it off, or solve the small average equation for an even count.

Find the median of 15, 30, 20, 10, 25, 35, 18, 21, 28.

A21B30C18D25

Find the median of 3, 9, 5, 11, 7, 13.

A7B9C8D10

The median of 2, 5, 8, x, 13, 17 (already in ascending order) is 9. Find x.

A8B9C10D11

Ten values are in ascending order. The median is 55. The 5th value is x and the 6th is y, with y βˆ’ x = 10. Find y.

A65B62C60D58

In the data 7, 10, 4, x, 14, 12, 6 arranged in ascending order the median is 8. Find x.

A9B8C7D10