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HCF & LCM · Topic 2 of 6

✖️ Product, Pairs & Multiples

3 exam question types, fully solved

There is one identity that powers most two-number questions in this chapter, and it is worth more marks than any other single fact here: the product rule.

HCF × LCM = product of the two numbers

For any two numbers and : . Rearrange it to find whatever is missing — a number, the HCF, or the LCM.

• Why it works: write and where is the HCF and are co-prime. Then , so .

• Counting pairs: from a product, ; from a sum, . Count only the co-prime splits — a shared factor would push the real HCF above .

• Warning: the product rule holds for two numbers only — never for three.

⚖️HCF & LCM MachineSame prime factors — lowest powers make the HCF, highest powers make the LCM
First
Second
Third (optional)
72=2³×3²
120=2³×3×5
HCF → only the primes shared by every number (highlighted), each at its LOWEST power. LCM → every prime that appears anywhere, each at its HIGHEST power.
HCF=2³×3=24
LCM=2³×3²×5=360
Check: HCF × LCM = 24 × 360 = 8,640
a × b = 72 × 120 = 8,640 — they match ✓
This identity works for exactly two numbers — it fails for three or more.

If the HCF is 6 and the LCM is 36, the product of the two numbers is .

📝Practice Questions

Q1HCF of two numbers is 8 and LCM is 48. If one number is 16, the other is:

Q2The product of two numbers is 2025 and their HCF is 15. Their LCM is:

Q3Product of two numbers is 1600 and HCF is 20. How many such pairs exist?

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Real exam questions — Product, Pairs & Multiples

3 question types · 12 solved examples from real SSC papers

One identity rules this topic: HCF × LCM = product of the two numbers. Write the numbers as HCF × (co-prime parts) and almost every question becomes a one-liner.

How to solve this type
For any TWO numbers: HCF×LCM=first×second\text{HCF}\times\text{LCM}=\text{first}\times\text{second}. Rearrange to find whatever is missing. If you are given the sum or difference too, write the numbers as h⋅ah\cdot a and h⋅bh\cdot b with a,ba,b co-prime, so ab=LCMHCFab=\dfrac{\text{LCM}}{\text{HCF}} — then split that into two co-prime factors. Warning: this identity holds only for two numbers, never three.

The HCF of two numbers is 11 and one number is 77. Their LCM is 693. Find the other number.

A88B77C99D121

HCF of two numbers is 12 and their product is 2160. Find their LCM.

A160B180C120D240

The LCM and HCF of two numbers are 72 and 12, and their sum is 60. Find the numbers.

A12 and 48B24 and 36C48 and 12D36 and 24

Two numbers differ by 10. Their LCM is 120 and HCF is 10. The sum of the numbers is:

A120B50C130D70