π Find the Missing Digit
1 exam question type, fully solvedThese questions hide one digit (shown as *, @, a letter, or a blank) and ask which value makes the whole number divisible. The skill is to pick the right rule and turn it into a single small equation in that unknown digit.
β’ Divisor 3 or 9: add the known digits, then choose the missing digit so the total is a multiple of 3 or 9. For the least digit, aim for the nearest multiple β e.g. if the known digits sum to 24, the next multiple of 9 is 27, so the missing digit is 3.
β’ Divisor 2, 5 or 10: only the last digit is fixed (even; 0 or 5; or 0).
β’ Divisor 4 or 8: only the last two or three digits matter, so you usually solve for a trailing digit.
β’ Composite divisor (18, 36, 72, β¦): split into co-prime factors and apply each rule. For example β the last-two-digit rule fixes one digit, the digit-sum rule the other.
Watch the wording: βleast valueβ wants the smallest digit, and a digit can only be 0β9, so an option like 10 is never valid.
For 234a56 to be divisible by 3, the known digits sum to ; the next multiple of 3 is 21, so .
Q1Find the least digit a so that 51a3 is divisible by 9.
Q2For 38a to be divisible by 6, the least value of a is:
Q3For 7a4 to be divisible by 9, what is a?
Real exam questions β Find the Missing Digit
1 question types Β· 5 solved examples from real SSC papersMatch the divisor to its rule, then turn the rule into one equation in the unknown digit.
Find the value of a so that 234a56 is divisible by 3.
Find the least value of @ so that 7@5471 is divisible by 9.
Find the least value of * so that 457643*4 is divisible by 18.
If 7A425B is divisible by 36, what is A β B?
If the 8-digit number 4432A43B is divisible by both 9 and 5, find A + B.
