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Compound Interest · Topic 6 of 6

🧩 Complex Multi-Step Problems

1 exam question type, fully solved

The toughest interest questions are rarely about a new formula. They bolt two simple conditions together — a CI fact tied to an SI fact, or one year's amount used to unlock the next — and hope you panic. The cure is always the same: split the problem into clean stages and carry one running number forward.

Break it into stages, then chase the invariant

Carry the amount forward. Treat each year as a step: multiply the current amount by the year's multiplier , then move on. After years the amount is .

Mixing SI and CI. Simple interest is flat — the same interest every year, so over years it is just percent of . Compound interest compounds — each year's interest earns its own interest next year. Turn each side into a single net percentage, then equate. Handy net CI rates: 10% for 2 yr = , 20% for 2 yr = , 10% for 3 yr = .

Year-on-year trick. The jump from one year's amount to the next is exactly one year's interest on the earlier amount, so . A clean ratio like means a 5% rate on sight.

Equal instalments. When a CI loan is cleared in equal yearly payments , each instalment's present value is found by dividing it back by the multiplier, and they must add up to the loan: Solve for — never just split equally.

Golden rule: find the simplest invariant first — often the flat SI, or a tidy ratio — before reaching for powers. Many “hard” questions collapse to a one-line calculation.

📈CI vs SI Growth ChartInteractive
04k9k13k17kPY1Y2Y3Y4Y5SI (linear)CI (exponential)
CI is always > SI for T > 1 year. The gap widens exponentially — this is the power of “interest on interest.”
YearSI AmountCI AmountDifference
1₹11,000.00₹11,000.00—
2₹12,000.00₹12,100.00₹100.00
3₹13,000.00₹13,310.00₹310.00
4₹14,000.00₹14,641.00₹641.00
5₹15,000.00₹16,105.10₹1,105.10

At CI a sum amounts to ₹2,420 in year 2 and ₹2,662 in year 3, so the year-3 interest = 2662 − 2420 = ₹.

📝Practice Questions

Q1A sum gives CI of ₹1,050 in 2 years and SI of ₹1,000 in 2 years at the same rate. The rate is:

Q2SI on a sum P at 5% for 4 years equals the CI on ₹10,000 at 10% for 2 years. Find P.

Q3At CI a sum amounts to ₹2,400 in 2 years and ₹2,520 in 3 years. The rate is:

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Real exam questions — Complex Multi-Step Problems

1 question types · 5 solved examples from real SSC papers

The hardest CI questions rarely need a new formula — they bolt two simple conditions together (a CI fact and an SI fact, or consecutive-year amounts) and trust you to panic. The fix is always the same: split into stages, turn each side into one net percentage, and grab the simplest invariant first. Tap any question to see the staged solution.

How to solve this type
These look scary because they stack conditions, but each one breaks into clean stages.
Mixing SI and CI: SI is *flat* — the same interest every year, so over TT years it is just R×TR\times T percent of PP. CI *compounds* — each year's interest earns its own interest next year. Turn each side into a single net percentage, then equate.
Net-rate shortcut: for 2 years at R%R\% the CI rate is 2R+R21002R+\dfrac{R^2}{100} (10% → 21%, 20% → 44%); the SI rate is simply R×TR\times T. Carry these forward instead of grinding out PP.
Year-on-year: the jump from one year's amount to the next is one year's interest on the earlier amount, so R=A<sub>n+1</sub>−AnAn×100R=\dfrac{A<sub>n+1</sub>-A_n}{A_n}\times100 — a clean ratio like 21:2021:20 means 5% on sight.
Always hunt the simplest invariant first (often the flat SI, or a tidy ratio) before touching powers.

The compound interest for 2 years is ₹1,050 and the simple interest for 2 years is ₹1,000 on the same sum at the same rate. Find the rate and the principal.

AR=10%, P=₹5,000BR=5%, P=₹10,000CR=5%, P=₹8,000DR=10%, P=₹4,000

The simple interest on a sum P at 7% per annum for 2 years equals twice the compound interest on ₹1,000 at 10% per annum for 2 years. Find P.

A₹4,000B₹3,000C₹2,000D₹5,000

The compound interest on a sum P for 3 years at 10% per annum is ₹33,100, and the simple interest on the same P at the same rate for 3 years is ₹30,000. Find P.

A₹1,00,000B₹1,10,000C₹80,000D₹90,000

At compound interest, a sum amounts to ₹8,820 at the end of year 2 and ₹9,261 at the end of year 3. Find the rate and the original sum.

AR=4%, P=₹8,000BR=5%, P=₹7,500CR=6%, P=₹7,500DR=5%, P=₹8,000

The compound interest on a sum P for 2 years at 10% per annum is ₹2,100. What is the compound interest on the same sum for 3 years?

A₹3,410B₹3,310C₹3,000D₹3,100