🧩 Complex Multi-Step Problems
1 exam question type, fully solvedThe toughest interest questions are rarely about a new formula. They bolt two simple conditions together — a CI fact tied to an SI fact, or one year's amount used to unlock the next — and hope you panic. The cure is always the same: split the problem into clean stages and carry one running number forward.
Carry the amount forward. Treat each year as a step: multiply the current amount by the year's multiplier , then move on. After years the amount is .
Mixing SI and CI. Simple interest is flat — the same interest every year, so over years it is just percent of . Compound interest compounds — each year's interest earns its own interest next year. Turn each side into a single net percentage, then equate. Handy net CI rates: 10% for 2 yr = , 20% for 2 yr = , 10% for 3 yr = .
Year-on-year trick. The jump from one year's amount to the next is exactly one year's interest on the earlier amount, so . A clean ratio like means a 5% rate on sight.
Equal instalments. When a CI loan is cleared in equal yearly payments , each instalment's present value is found by dividing it back by the multiplier, and they must add up to the loan: Solve for — never just split equally.
Golden rule: find the simplest invariant first — often the flat SI, or a tidy ratio — before reaching for powers. Many “hard” questions collapse to a one-line calculation.
| Year | SI Amount | CI Amount | Difference |
|---|---|---|---|
| 1 | ₹11,000.00 | ₹11,000.00 | — |
| 2 | ₹12,000.00 | ₹12,100.00 | ₹100.00 |
| 3 | ₹13,000.00 | ₹13,310.00 | ₹310.00 |
| 4 | ₹14,000.00 | ₹14,641.00 | ₹641.00 |
| 5 | ₹15,000.00 | ₹16,105.10 | ₹1,105.10 |
At CI a sum amounts to ₹2,420 in year 2 and ₹2,662 in year 3, so the year-3 interest = 2662 − 2420 = ₹.
Q1A sum gives CI of ₹1,050 in 2 years and SI of ₹1,000 in 2 years at the same rate. The rate is:
Q2SI on a sum P at 5% for 4 years equals the CI on ₹10,000 at 10% for 2 years. Find P.
Q3At CI a sum amounts to ₹2,400 in 2 years and ₹2,520 in 3 years. The rate is:
Real exam questions — Complex Multi-Step Problems
1 question types · 5 solved examples from real SSC papersThe hardest CI questions rarely need a new formula — they bolt two simple conditions together (a CI fact and an SI fact, or consecutive-year amounts) and trust you to panic. The fix is always the same: split into stages, turn each side into one net percentage, and grab the simplest invariant first. Tap any question to see the staged solution.
Mixing SI and CI: SI is *flat* — the same interest every year, so over years it is just percent of . CI *compounds* — each year's interest earns its own interest next year. Turn each side into a single net percentage, then equate.
Net-rate shortcut: for 2 years at the CI rate is (10% → 21%, 20% → 44%); the SI rate is simply . Carry these forward instead of grinding out .
Year-on-year: the jump from one year's amount to the next is one year's interest on the earlier amount, so — a clean ratio like means 5% on sight.
Always hunt the simplest invariant first (often the flat SI, or a tidy ratio) before touching powers.
The compound interest for 2 years is ₹1,050 and the simple interest for 2 years is ₹1,000 on the same sum at the same rate. Find the rate and the principal.
The simple interest on a sum P at 7% per annum for 2 years equals twice the compound interest on ₹1,000 at 10% per annum for 2 years. Find P.
The compound interest on a sum P for 3 years at 10% per annum is ₹33,100, and the simple interest on the same P at the same rate for 3 years is ₹30,000. Find P.
At compound interest, a sum amounts to ₹8,820 at the end of year 2 and ₹9,261 at the end of year 3. Find the rate and the original sum.
The compound interest on a sum P for 2 years at 10% per annum is ₹2,100. What is the compound interest on the same sum for 3 years?
