โ† All topics๐Ÿ”— a, b, c RelationshipsMaths
Averages ยท Topic 3 of 6

๐Ÿ”— a, b, c Relationships

2 exam question types, fully solved

Here you are told the average of a pair or a triple of unknowns โ€” say the average of and , and of and โ€” and asked for one value or a difference. The trick is to stop thinking in averages and switch to sums.

Multiply by the count, then cancel the shared letter

Step 1 โ€” average to sum. โ€œAverage of two is 50โ€ means their sum is . Always multiply the average by how many numbers it covers (2 for a pair, 3 for a triple) before doing anything else.

Step 2 โ€” subtract overlapping sums. When two groups share a member, subtracting their sums makes the shared letter vanish:

The 5-second shortcut. For two same-size groups, the difference of the unique members is twice the difference of the averages:

For bigger systems (three triple-averages), add all the equations: each letter shows up twice, so the grand total is half the combined sum, and you peel off one variable at a time.

๐Ÿ“ŠAverage Builderinteractive
avg = 5.4
4
7
2
9
5
Sum (S)
27
Count (N)
5
Average
5.4
Average = 27 รท 5 = 5.4

If and , then .

๐Ÿ“Practice Questions

Q1The average of P and Q is 45; the average of Q and R is 38. Find P โˆ’ R.

Q2The average of a, b, c is 20; the average of b, c, d is 25. Then d โˆ’ a equals:

Q3The average of 4 numbers is 50. One is replaced by 70 and the average becomes 55. The replaced number was:

๐Ÿ“š

Real exam questions โ€” a, b, c Relationships

2 question types ยท 8 solved examples from real SSC papers

Turn every “average of two” into a sum by multiplying by 2, then add or subtract the sums to cancel shared letters.

How to solve this type
First rule: turn every “average of two” into a sum by multiplying by 2. The average of xx and yy being 5050 means x+y=100x + y = 100 โ€” work with the sums, never the raw averages.
When two pairs share a member (like a+ba+b and b+cb+c), subtract the sums to cancel the shared letter: (b+c)โˆ’(a+b)=cโˆ’a(b+c)-(a+b) = c - a.
Handy shortcut: if two pairs of the same size differ in average by dd, the unique members differ by 2d2d. So if avg(a,b)(a,b) and avg(b,c)(b,c) differ by 9, then aโˆ’c=18a - c = 18.

The average of x and y is 50. The average of y and z is 60. Find z โˆ’ x.

A15B18C20D25

The average of three numbers a, b, c is 40. The average of a and b is 36. Find c.

A54B50C48D52

The average of A and B is 25, the average of B and C is 18, and C = 12. Find A.

A22B18C20D26

The average of S1 and S2 is 30 more than the average of S2 and S3. If S3 = 50, find S1.

A95B110C80D105