๐ a, b, c Relationships
2 exam question types, fully solvedHere you are told the average of a pair or a triple of unknowns โ say the average of and , and of and โ and asked for one value or a difference. The trick is to stop thinking in averages and switch to sums.
Step 1 โ average to sum. โAverage of two is 50โ means their sum is . Always multiply the average by how many numbers it covers (2 for a pair, 3 for a triple) before doing anything else.
Step 2 โ subtract overlapping sums. When two groups share a member, subtracting their sums makes the shared letter vanish:
The 5-second shortcut. For two same-size groups, the difference of the unique members is twice the difference of the averages:
For bigger systems (three triple-averages), add all the equations: each letter shows up twice, so the grand total is half the combined sum, and you peel off one variable at a time.
If and , then .
Q1The average of P and Q is 45; the average of Q and R is 38. Find P โ R.
Q2The average of a, b, c is 20; the average of b, c, d is 25. Then d โ a equals:
Q3The average of 4 numbers is 50. One is replaced by 70 and the average becomes 55. The replaced number was:
Real exam questions โ a, b, c Relationships
2 question types ยท 8 solved examples from real SSC papersTurn every “average of two” into a sum by multiplying by 2, then add or subtract the sums to cancel shared letters.
When two pairs share a member (like and ), subtract the sums to cancel the shared letter: .
Handy shortcut: if two pairs of the same size differ in average by , the unique members differ by . So if avg and avg differ by 9, then .
The average of x and y is 50. The average of y and z is 60. Find z โ x.
The average of three numbers a, b, c is 40. The average of a and b is 36. Find c.
The average of A and B is 25, the average of B and C is 18, and C = 12. Find A.
The average of S1 and S2 is 30 more than the average of S2 and S3. If S3 = 50, find S1.
