← All topics📈 Variation & PolynomialsMaths
Algebra · Topic 7 of 7

📈 Variation & Polynomials

2 exam question types, fully solved

Variation is the maths of “as one quantity changes, how does the other respond?” The whole method is: find the constant that links them, then scale. We finish the chapter with a few smart ways to evaluate polynomials for awkward numbers.

Find the constant, then scale

• Direct variation: means . Use the first pair to find , then apply it. As grows, grows.

• Inverse variation: means the product stays fixed. Multiply one variable by and the other is divided by .

• Chained powers: treat like and substitute. If and , then .

Smart polynomial values: re-shape before you compute. , and for close numbers .

🔷Identity ExplorerPick an identity to see its proof
(a+b)² = a² + 2ab + b²

Expand as (a+b)×(a+b). The square area splits into 4 rectangles: a², ab, ab, b².

a²ababb²ab
Numeric Verification
LHS: (3+2)² = 25
RHS: 3²+2·3·2+2² = 25
✓ LHS = RHS — identity verified!

If and when , then  (so ).

📝Practice Questions

Q1If y varies directly as x and y = 12 when x = 3, find y when x = 7.

Q2P varies inversely as Q. If P = 10 when Q = 6, find P when Q = 15.

Q3If p = 49, the value of p(p² + 3p + 3) follows (p+1)³ − 1. The cube used is:

📚

Real exam questions — Variation & Polynomials

2 question types · 8 solved examples from real SSC papers

Variation is just “find the constant, then scale”. Polynomial-value questions reward re-shaping the expression into a clean cube before you compute.

How to solve this type
Direct: y∝xy\propto x means y=kxy=kx — find kk from the first pair, then use it. Inverse: y∝1xy\propto\dfrac1x means xy=kxy=k stays constant. Powers carry through: x∝y2x\propto y^2 and y∝zy\propto\sqrt z chain into x∝zx\propto z. Ratio shortcut for inverse: multiply one variable by nn ⇒ divide the other by nn.

If y∝xy\propto x and y=15y=15 when x=5x=5, find yy when x=12x=12.

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PP varies inversely as QQ. P=15P=15 when Q=4Q=4. Find PP when Q=12Q=12.

A55B4545C2020D33

If x∝y2x\propto y^2 and y∝zy\propto\sqrt z, then xx varies as:

Az\sqrt zBzzCz2z^2D1z\dfrac1z

If a∝b3a\propto b^3 and a=27a=27 when b=3b=3, find bb when a=64a=64.

A88B66C22D44